Standardizing an SAT score
A student scores 1200 on the SAT. The population mean is μ = 1050 and the standard deviation is σ = 200. How many standard deviations above the mean is this score?
Resultz = 0.75 (about the 77th percentile)
Apply z = (x − μ) / σ. Subtract the mean: 1200 − 1050 = 150. Divide by the standard deviation: 150 / 200 = 0.75. A z of 0.75 corresponds to a left-tail probability of roughly 0.7734 on the standard normal, so the student scored higher than about 77% of test-takers and is in the top 23%. The same procedure converts any raw measurement (lab result, height, return on investment) into a unit-free score you can compare across different scales.